f(0)=2x^2-5

Solution for f(0)=2x^2-5 equation:

Simplifying
f(0) = 2x2 + -5

Reorder the terms for easier multiplication:
0f = 2x2 + -5

Anything times zero is zero.
0f = 2x2 + -5

Reorder the terms:
0 = -5 + 2x2

Solving
0 = -5 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
0 + -2x2 = -5 + 2x2 + -2x2
Remove the zero:
-2x2 = -5 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-2x2 = -5 + 0
-2x2 = -5

Divide each side by '-2'.
x2 = 2.5

Simplifying
x2 = 2.5

Take the square root of each side:
x = {-1.58113883, 1.58113883}